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M417 Homework 3 Solutions Spring 04 (1) (a) For any subsets C 1,C 2 ⊂ A, show that f(C 1 ∪ C 2) = f(C 1) ∪ f(C 2) We must show that any element of f(C 1 ∪ C 2) is an element of f(C 1) ∪ f(C 2), and vice versaSo let y ∈ f(C 1 ∪ C 2) Then y = f(x) for some x ∈ C 1 ∪ C 2If x ∈ C. The Fokker CX was originally designed for the Royal Dutch East Indies Army, in order to replace the Fokker CV Like all Fokker aircraft of that time, it was of mixed construction, with wooden wing structures and a welded steel tube frame covered with aluminium plates at the front of the aircraft and with fabric at the rear. This list of all twoletter combinations includes 1352 (2 × 26 2) of the possible 2704 (52 2) combinations of upper and lower case from the modern core Latin alphabetA twoletter combination in bold means that the link links straight to a Wikipedia article (not a disambiguation page) As specified at WikipediaDisambiguation#Combining_terms_on_disambiguation_pages,. M417 Homework 3 Solutions Spring 04 (1) (a) For any subsets C 1,C 2 ⊂ A, show that f(C 1 ∪ C 2) = f(C 1) ∪ f(C 2) We must show that any element of f(C 1 ∪ C 2) is an element of f(C 1) ∪ f(C 2), and vice versaSo let y ∈ f(C 1 ∪ C 2) Then y = f(x) for some x ∈ C 1 ∪ C 2If x ∈ C.
