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X e h O X z C X g 摜 ̉摜 X g I X e h O X f B Y j v Z X ̃C X g I X e h O X f B Y j v Z X ̃C X g f B Y j v Z X ̃X e h O X C X g Y. L B e t Q I W i } j A b N ̔ T C g \ t g s B P i w 痘 p ł A ̍D ݂̃R e c s C g œ \ ł I U ̃ A ^ C w { ł A ǂ̍ i l C ̂ A ` F b N 邱 Ƃ \ I e ҁF y X K ` f z Y _ c R g. Let a^x = b^y = c^z = abc = k a^x = k => a = k^ (1/x) Similarly, b = k^(1/y) and c = k^(1/z) Now abc = k => k^(1/x) k^(1/y)k^(1/z) = k => k^{(1/x 1/y 1/ z)} = k^1 Since the bases are same we can equate the indices Hence we get 1/x 1/y 1/.
It is given that z=f(x, y), x=g(s, t) and y=h(s, t), So in order to find {eq}\frac{dz}{dt} {/eq}, we will use the partial derivative and the chain. See the answer Find ∂z/∂x and ∂z/∂y (a. F B Y j v Z X v ~ A R N V V f A A T E r i h F1500 l p G { T C g A ݂ Ȃ̐ 2 A ǂ݉ G { I F f B Y j v Z X u V f v ̊G { ͂ o Ă ܂ A ̊G { ̓ ǂݕ ̂ ߂ɁA1 ͗ Ăɂ A e ł ܂ B. V Z X @ R X v @ @ f B Y j @ @ v c F @ P @ x @ A i Ɛ ̏ @ G T h X R X ` s X v Z X f B Y j v Z X ̃ s X ł B l C f B Y j v Z X ̂Ƃ Ă Ȃ肫 R X ` B v Z X D ȏ ̎q 喞 ̉ s X ł B v g ɂ ł H h X ̎ E A i Ɛ ̏ @ G T E ̏ ̃ v c F @ v c F E P E Ɩ b @ x Z b g e s X h X ̂ T C Y 110 g Fcm 1 g F1101cm 1 E E E @ i F.
