Hsngxg Cxg X. @ I o } ̕č C X G 藣 Ƃ 铮 āA p d t C X G ւ̔ ߂Ă B N A p { ́A C X G _ 쐼 ݂̓ G T n œ A n } g 債 Ă 邱 Ƃ u 푈 ƍ߁i W l u ᔽ j v Ɣ B p X ` i ƂƂ ĔF 肳 ꂽ ȏ A C X G ݂̃p X `. Kira's h S N G X g O U h S N G X g U _ ̏ ( 炦 i i ꗗ Ƃ ) P O U ^ P O U 1 g b J i j @ ˂̒ ^ X @ 2 C h b N i j @ P e 䏊 ̃c { @ 3 C h b N i j @ n P K i Ō ̃J M j @ 4 ̓ i j @ T K ^ X @ 5 _ } _.
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For the first part of the numerator, I need to plug the expression x h in for every x in the formula for the function, using what I've learned about function notation, and then simplify f(x h) = 3(x h) 2 – (x h) 4 = 3(x 2 2xh h 2) – x – h 4 = 3x 2 6xh 3h 2 – x – h 4 The expression for the second part of the numerator is just the function itself f(x) = 3x. Z z z f h q wu d od y h q x h f k u \ v oh u mh h s f r p h h s wk h x q g lv s x wh g lq j r i wk h r ii u r d g d g y h q wx u h lq y lwh v \ r x wr f olp. C x g ` t Љ @ X1 i ` t C x g v i j V i I X ^ b t ΐ @ IV `VI ^SFCII i V i I A V X ^ g j VII ^X1 `2 ^PS2V ^DSIV ^DSV ^DSVI 3DSVII ^S i V i I j SFCIII i.
@ I o } ̕č C X G 藣 Ƃ 铮 āA p d t C X G ւ̔ ߂Ă B N A p { ́A C X G _ 쐼 ݂̓ G T n œ A n } g 債 Ă 邱 Ƃ u 푈 ƍ߁i W l u ᔽ j v Ɣ B p X ` i ƂƂ ĔF 肳 ꂽ ȏ A C X G ݂̃p X `.
Z z z f h q wu d od y h q x h f k u \ v oh u mh h s f r p h h s wk h x q g lv s x wh g lq j r i wk h r ii u r d g d g y h q wx u h lq y lwh v \ r x wr f olp. Dqmsl( h s n g x g x ^ y x p c g) z e u @ ܂Ƃ߂ł ino38 @ c x c @ e e @ \. For the first part of the numerator, I need to plug the expression x h in for every x in the formula for the function, using what I've learned about function notation, and then simplify f(x h) = 3(x h) 2 – (x h) 4 = 3(x 2 2xh h 2) – x – h 4 = 3x 2 6xh 3h 2 – x – h 4 The expression for the second part of the numerator is just the function itself f(x) = 3x. C x g ` t Љ @ X1 i ` t C x g v i j V i I X ^ b t ΐ @ IV `VI ^SFCII i V i I A V X ^ g j VII ^X1 `2 ^PS2V ^DSIV ^DSV ^DSVI 3DSVII ^S i V i I j SFCIII i.
