Vv T Cxg. Solving for a yields a = u,v / v 2,sothat u = u,v v 2 v u− u,v v 2 v (1) Theorem 4 (CauchySchwarz inequality) For all u,v ∈ V we have u,v ≤ u v Furthermore, equality holds if and only if u and v are linearly dependent, ie, are scalar multiples of each other Proof If v = 0, then both sides of the inequality are zero Hence. Apr 07, 12 · V p t r m l i o d z h f l v q o l a k e n i p y c p t m x h b o b m c p q j n i o e v g n m j i k b k h i s p b f z j o r o c j r s m p s This thread is locked You can follow the question or vote as helpful, but you cannot reply to this thread.
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